/usr/share/pyshared/musicbrainz2/utils.py is in python-musicbrainz2 0.7.4-1.
This file is owned by root:root, with mode 0o644.
The actual contents of the file can be viewed below.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 153 154 155 156 157 158 159 160 161 162 163 164 165 166 167 168 169 170 171 172 173 174 175 176 177 178 179 180 181 182 183 184 185 186 187 188 189 190 191 192 193 194 195 196 197 198 199 200 201 202 203 | """Various utilities to simplify common tasks.
This module contains helper functions to make common tasks easier.
@author: Matthias Friedrich <matt@mafr.de>
"""
__revision__ = '$Id: utils.py 13322 2011-11-03 13:38:06Z luks $'
import re
import urlparse
__all__ = [
'extractUuid', 'extractFragment', 'extractEntityType',
'getReleaseTypeName', 'getCountryName', 'getLanguageName',
'getScriptName',
]
# A pattern to split the path part of an absolute MB URI.
PATH_PATTERN = '^/(artist|release|track|label|release-group)/([^/]*)$'
def extractUuid(uriStr, resType=None):
"""Extract the UUID part from a MusicBrainz identifier.
This function takes a MusicBrainz ID (an absolute URI) as the input
and returns the UUID part of the URI, thus turning it into a relative
URI. If C{uriStr} is None or a relative URI, then it is returned
unchanged.
The C{resType} parameter can be used for error checking. Set it to
'artist', 'release', or 'track' to make sure C{uriStr} is a
syntactically valid MusicBrainz identifier of the given resource
type. If it isn't, a C{ValueError} exception is raised.
This error checking only works if C{uriStr} is an absolute URI, of
course.
Example:
>>> from musicbrainz2.utils import extractUuid
>>> extractUuid('http://musicbrainz.org/artist/c0b2500e-0cef-4130-869d-732b23ed9df5', 'artist')
'c0b2500e-0cef-4130-869d-732b23ed9df5'
>>>
@param uriStr: a string containing a MusicBrainz ID (an URI), or None
@param resType: a string containing a resource type
@return: a string containing a relative URI, or None
@raise ValueError: the given URI is no valid MusicBrainz ID
"""
if uriStr is None:
return None
(scheme, netloc, path) = urlparse.urlparse(uriStr)[:3]
if scheme == '':
return uriStr # no URI, probably already the UUID
if scheme != 'http' or netloc != 'musicbrainz.org':
raise ValueError('%s is no MB ID.' % uriStr)
m = re.match(PATH_PATTERN, path)
if m:
if resType is None:
return m.group(2)
else:
if m.group(1) == resType:
return m.group(2)
else:
raise ValueError('expected "%s" Id' % resType)
else:
raise ValueError('%s is no valid MB ID.' % uriStr)
def extractFragment(uriStr, uriPrefix=None):
"""Extract the fragment part from a URI.
If C{uriStr} is None or no absolute URI, then it is returned unchanged.
The C{uriPrefix} parameter can be used for error checking. If C{uriStr}
is an absolute URI, then the function checks if it starts with
C{uriPrefix}. If it doesn't, a C{ValueError} exception is raised.
@param uriStr: a string containing an absolute URI
@param uriPrefix: a string containing an URI prefix
@return: a string containing the fragment, or None
@raise ValueError: the given URI doesn't start with C{uriPrefix}
"""
if uriStr is None:
return None
(scheme, netloc, path, params, query, frag) = urlparse.urlparse(uriStr)
if scheme == '':
return uriStr # this is no URI
if uriPrefix is None or uriStr.startswith(uriPrefix):
return frag
else:
raise ValueError("prefix doesn't match URI %s" % uriStr)
def extractEntityType(uriStr):
"""Returns the entity type an entity URI is referring to.
@param uriStr: a string containing an absolute entity URI
@return: a string containing 'artist', 'release', 'track', or 'label'
@raise ValueError: if the given URI is no valid MusicBrainz ID
"""
if uriStr is None:
raise ValueError('None is no valid entity URI')
(scheme, netloc, path) = urlparse.urlparse(uriStr)[:3]
if scheme == '':
raise ValueError('%s is no absolute MB ID.' % uriStr)
if scheme != 'http' or netloc != 'musicbrainz.org':
raise ValueError('%s is no MB ID.' % uriStr)
m = re.match(PATH_PATTERN, path)
if m:
return m.group(1)
else:
raise ValueError('%s is no valid MB ID.' % uriStr)
def getReleaseTypeName(releaseType):
"""Returns the name of a release type URI.
@param releaseType: a string containing a release type URI
@return: a string containing a printable name for the release type
@see: L{musicbrainz2.model.Release}
"""
from musicbrainz2.data.releasetypenames import releaseTypeNames
return releaseTypeNames.get(releaseType)
def getCountryName(id_):
"""Returns a country's name based on an ISO-3166 country code.
The country table this function is based on has been modified for
MusicBrainz purposes by using the extension mechanism defined in
ISO-3166. All IDs are still valid ISO-3166 country codes, but some
IDs have been added to include historic countries and some of the
country names have been modified to make them better suited for
display purposes.
If the country ID is not found, None is returned. This may happen
for example, when new countries are added to the MusicBrainz web
service which aren't known to this library yet.
@param id_: a two-letter upper case string containing an ISO-3166 code
@return: a string containing the country's name, or None
@see: L{musicbrainz2.model}
"""
from musicbrainz2.data.countrynames import countryNames
return countryNames.get(id_)
def getLanguageName(id_):
"""Returns a language name based on an ISO-639-2/T code.
This function uses a subset of the ISO-639-2/T code table to map
language IDs (terminologic, not bibliographic ones!) to names.
@param id_: a three-letter upper case string containing an ISO-639-2/T code
@return: a string containing the language's name, or None
@see: L{musicbrainz2.model}
"""
from musicbrainz2.data.languagenames import languageNames
return languageNames.get(id_)
def getScriptName(id_):
"""Returns a script name based on an ISO-15924 code.
This function uses a subset of the ISO-15924 code table to map
script IDs to names.
@param id_: a four-letter string containing an ISO-15924 script code
@return: a string containing the script's name, or None
@see: L{musicbrainz2.model}
"""
from musicbrainz2.data.scriptnames import scriptNames
return scriptNames.get(id_)
# EOF
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