/usr/share/SBMLToolbox/Simulation/DealWithPiecewise.m is in sbmltoolbox 4.1.0-3.
This file is owned by root:root, with mode 0o644.
The actual contents of the file can be viewed below.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 153 154 155 156 157 158 159 160 161 162 163 164 165 166 167 168 169 170 171 | function Elements = DealWithPiecewise(OriginalFormula)
% elements = DealWithPiecewise(formula)
%
% Takes
%
% 1. formula, a string representation of a math expression that contains the MathML piecewise function
%
% Returns
%
% 1. an array of the three components of the piecewise function
%
% *EXAMPLE:*
%
% elements = DealWithPiecewise('piecewise(le(s2,4),1.5,0.05)')
%
% = 'le(s2,4)' '1.5' '0.05'
%
% *NOTE:* The function cannot deal with a piecewise statement with more
% than three elements.
%<!---------------------------------------------------------------------------
% This file is part of SBMLToolbox. Please visit http://sbml.org for more
% information about SBML, and the latest version of SBMLToolbox.
%
% Copyright (C) 2009-2012 jointly by the following organizations:
% 1. California Institute of Technology, Pasadena, CA, USA
% 2. EMBL European Bioinformatics Institute (EBML-EBI), Hinxton, UK
%
% Copyright (C) 2006-2008 jointly by the following organizations:
% 1. California Institute of Technology, Pasadena, CA, USA
% 2. University of Hertfordshire, Hatfield, UK
%
% Copyright (C) 2003-2005 jointly by the following organizations:
% 1. California Institute of Technology, Pasadena, CA, USA
% 2. Japan Science and Technology Agency, Japan
% 3. University of Hertfordshire, Hatfield, UK
%
% SBMLToolbox is free software; you can redistribute it and/or modify it
% under the terms of the GNU Lesser General Public License as published by
% the Free Software Foundation. A copy of the license agreement is provided
% in the file named "LICENSE.txt" included with this software distribution.
%----------------------------------------------------------------------- -->
OriginalFormula = LoseWhiteSpace(OriginalFormula);
OpeningBracketIndex = find((ismember(OriginalFormula, '(')) == 1);
ClosingBracketIndex = find((ismember(OriginalFormula, ')')) == 1);
CommaIndex = find((ismember(OriginalFormula, ',')) == 1);
%pair the brackets
Pairs = PairBrackets(OriginalFormula);
Start = findstr(OriginalFormula, 'piecewise');
if (length(Start) == 0)
error('DealWithPiecewise(formula)\n%s', 'piecewise either does not occur in the formula');
end;
% find the commas that are between the arguments of the piecwise expression
% not those that may be part of the argument
% e.g. 'piecewise(gt(d,e),lt(2,e),gt(f,d))'
% | |
% relevant commas
piecewiseBrackets = 1;
while(piecewiseBrackets <= length(OpeningBracketIndex))
if (Pairs(piecewiseBrackets, 1) > Start(1))
break;
else
piecewiseBrackets = piecewiseBrackets + 1;
end;
end;
for i = 1:length(CommaIndex)
% if comma is outside the piecwise brackets not relevant
if (CommaIndex(i) < Pairs(piecewiseBrackets, 1))
CommaIndex(i) = 0;
elseif(CommaIndex(i) > Pairs(piecewiseBrackets, 2))
CommaIndex(i) = 0;
end;
for j = piecewiseBrackets+1:length(OpeningBracketIndex)
if ((CommaIndex(i) > Pairs(j, 1)) && (CommaIndex(i) < Pairs(j, 2)))
CommaIndex(i) = 0;
end;
end;
end;
NonZeros = find(CommaIndex ~= 0);
% if there is only one relevant comma
% implies only two arguments
% MATLAB can deal with the OriginalFormula
if (length(NonZeros) ~= 2)
error('Not enough arguments passed')
end;
% get elements that represent the arguments of the piecewise expression
% as an array of character arrays
% e.g. first element is between opening bracket and first relevant comma
% next elements are between relevant commas
% last element is between last relevant comma and closing bracket
j = Pairs(piecewiseBrackets, 1);
ElementNumber = 1;
for i = 1:length(NonZeros)
element = '';
j = j+1;
while (j <= CommaIndex(NonZeros(i)) - 1)
element = strcat(element, OriginalFormula(j));
j = j + 1;
end;
% if (findstr(element, 'piecewise'))
% element = DealWithPiecewise(element);
% end;
Elements{ElementNumber} = element;
ElementNumber = ElementNumber + 1;
end;
element = '';
j = j+1;
while (j < Pairs(piecewiseBrackets, 2))
element = strcat(element, OriginalFormula(j));
j = j + 1;
end;
% if (findstr(element, 'piecewise'))
% element = DealWithPiecewise(element);
% end;
Elements{ElementNumber} = element;
% check for a sign in front of leading brackets
% if (Pairs (1,1) ~= 1)
% if strcmp(OriginalFormula(1), '-')
% Elements{1} = strcat('-',Elements{1});
% Elements{3} = strcat('-',Elements{3});
% end;
% end;
%
% what if there is smething before or after the piecewise bit
before = '';
after = '';
pw = matchFunctionName(OriginalFormula, 'piecewise');
if (pw(1) ~= 1)
before = OriginalFormula(1:pw(1)-1);
end;
if (Pairs(piecewiseBrackets, 2) ~= length(OriginalFormula))
after = OriginalFormula(Pairs(piecewiseBrackets, 2)+1:end);
end;
Elements{1} = strcat(before ,Elements{1}, after);
Elements{3} = strcat(before ,Elements{3}, after);
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