/usr/share/pyshared/bzrlib/version.py is in python-bzrlib 2.5.0-2ubuntu2.
This file is owned by root:root, with mode 0o644.
The actual contents of the file can be viewed below.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 | # Copyright (C) 2006-2010 Canonical Ltd
#
# This program is free software; you can redistribute it and/or modify
# it under the terms of the GNU General Public License as published by
# the Free Software Foundation; either version 2 of the License, or
# (at your option) any later version.
#
# This program is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
# GNU General Public License for more details.
#
# You should have received a copy of the GNU General Public License
# along with this program; if not, write to the Free Software
# Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA 02110-1301 USA
"""Report on version of bzrlib"""
from __future__ import absolute_import
import os
import sys
import bzrlib
from bzrlib import (
config,
controldir,
errors,
osutils,
trace,
)
def show_version(show_config=True, show_copyright=True, to_file=None):
import platform
if to_file is None:
to_file = sys.stdout
to_file.write("Bazaar (bzr) %s\n" % bzrlib.__version__)
# is bzrlib itself in a branch?
src_tree = _get_bzr_source_tree()
if src_tree:
src_revision_id = src_tree.last_revision()
revno = src_tree.branch.revision_id_to_revno(src_revision_id)
to_file.write(" from bzr checkout %s\n" % (src_tree.basedir,))
to_file.write(" revision: %s\n" % (revno,))
to_file.write(" revid: %s\n" % (src_revision_id,))
to_file.write(" branch nick: %s\n" % (src_tree.branch.nick,))
to_file.write(" Python interpreter: ")
# show path to python interpreter
# (bzr.exe use python interpreter from pythonXY.dll
# but sys.executable point to bzr.exe itself)
# however, sys.frozen exists if running from bzr.exe
# see http://www.py2exe.org/index.cgi/Py2exeEnvironment
if getattr(sys, 'frozen', None) is None: # if not bzr.exe
to_file.write(sys.executable + ' ')
else:
# pythonXY.dll
basedir = os.path.dirname(sys.executable)
python_dll = "python%d%d.dll" % sys.version_info[:2]
to_file.write(os.path.join(basedir, python_dll) + ' ')
# and now version of python interpreter
to_file.write(bzrlib._format_version_tuple(sys.version_info))
to_file.write('\n')
to_file.write(" Python standard library:" + ' ')
to_file.write(os.path.dirname(os.__file__) + '\n')
to_file.write(" Platform: %s\n" % platform.platform(aliased=1))
to_file.write(" bzrlib: ")
if len(bzrlib.__path__) > 1:
# print repr, which is a good enough way of making it clear it's
# more than one element (eg ['/foo/bar', '/foo/bzr'])
to_file.write(repr(bzrlib.__path__) + '\n')
else:
to_file.write(bzrlib.__path__[0] + '\n')
if show_config:
config_dir = osutils.normpath(config.config_dir()) # use native slashes
if not isinstance(config_dir, unicode):
config_dir = config_dir.decode(osutils.get_user_encoding())
to_file.write(" Bazaar configuration: %s\n" % (config_dir,))
to_file.write(" Bazaar log file: ")
to_file.write(trace._bzr_log_filename + '\n')
if show_copyright:
to_file.write('\n')
to_file.write(bzrlib.__copyright__ + '\n')
to_file.write("http://bazaar.canonical.com/\n")
to_file.write('\n')
to_file.write("bzr comes with ABSOLUTELY NO WARRANTY. bzr is free software, and\n")
to_file.write("you may use, modify and redistribute it under the terms of the GNU\n")
to_file.write("General Public License version 2 or later.\n")
to_file.write("\nBazaar is part of the GNU Project to produce a free operating "
"system.\n")
to_file.write('\n')
def _get_bzr_source_tree():
"""Return the WorkingTree for bzr source, if any.
If bzr is not being run from its working tree, returns None.
"""
try:
control = controldir.ControlDir.open_containing(__file__)[0]
return control.open_workingtree(recommend_upgrade=False)
except (errors.NotBranchError, errors.UnknownFormatError,
errors.NoWorkingTree):
return None
|