/usr/share/pyshared/Wammu/App.py is in wammu 0.36-1.
This file is owned by root:root, with mode 0o644.
The actual contents of the file can be viewed below.
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# vim: expandtab sw=4 ts=4 sts=4:
'''
Wammu - Phone manager
Main Wammu application
'''
__author__ = 'Michal Čihař'
__email__ = 'michal@cihar.com'
__license__ = '''
Copyright © 2003 - 2010 Michal Čihař
This program is free software; you can redistribute it and/or modify it
under the terms of the GNU General Public License version 2 as published by
the Free Software Foundation.
This program is distributed in the hope that it will be useful, but WITHOUT
ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or
FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public License for
more details.
You should have received a copy of the GNU General Public License along with
this program; if not, write to the Free Software Foundation, Inc.,
51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA
'''
import wx
import sys
import Wammu.Main
import Wammu.Error
from Wammu.Locales import StrConv
class WammuApp(wx.App):
'''
Wammu appliction class, it initializes wx and creates main Wammu window.
'''
def OnInit(self):
'''
wxWindows call this method to initialize the application.
'''
self.SetAppName('Wammu')
vendor = StrConv(u'Michal Čihař')
if vendor.find('?') != -1:
vendor = 'Michal Čihař'
self.SetVendorName(vendor)
wx.InitAllImageHandlers()
frame = Wammu.Main.WammuFrame(None, -1)
Wammu.Error.HANDLER_PARENT = frame
frame.Show(True)
frame.PostInit(self)
self.SetTopWindow(frame)
# Return a success flag
return True
def Run():
'''
Wrapper to execute Wammu. Installs graphical error handler and launches
WammuApp.
'''
try:
sys.excepthook = Wammu.Error.Handler
except:
print _('Failed to set exception handler.')
app = WammuApp()
app.MainLoop()
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