/usr/include/dieharder/diehard_bitstream.h is in libdieharder-dev 3.31.1-4.
This file is owned by root:root, with mode 0o644.
The actual contents of the file can be viewed below.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 | /*
* diehard_bitstream test header.
*/
/*
* function prototype
*/
int diehard_bitstream(Test **test,int irun);
static Dtest diehard_bitstream_dtest __attribute__((unused)) = {
"Diehard Bitstream Test",
"diehard_bitstream",
"\n\
#==================================================================\n\
# Diehard Bitstream Test.\n\
# The file under test is viewed as a stream of bits. Call them \n\
# b1,b2,... . Consider an alphabet with two \"letters\", 0 and 1 \n\
# and think of the stream of bits as a succession of 20-letter \n\
# \"words\", overlapping. Thus the first word is b1b2...b20, the \n\
# second is b2b3...b21, and so on. The bitstream test counts \n\
# the number of missing 20-letter (20-bit) words in a string of \n\
# 2^21 overlapping 20-letter words. There are 2^20 possible 20 \n\
# letter words. For a truly random string of 2^21+19 bits, the \n\
# number of missing words j should be (very close to) normally \n\
# distributed with mean 141,909 and sigma 428. Thus \n\
# (j-141909)/428 should be a standard normal variate (z score) \n\
# that leads to a uniform [0,1) p value. The test is repeated \n\
# twenty times. \n\
#\n\
# NOTE WELL!\n\
#\n\
# The test is repeated 100 times by default in dieharder, but the\n\
# size of the sample is fixed (tsamples cannot/should not be\n\
# varied from the default). The sigma of this test REQUIRES the\n\
# use of overlapping samples, and overlapping samples are not\n\
# independent. If one uses the non-overlapping version of this\n\
# test, sigma = 290 is used instead, smaller because now there\n\
# are 2^21 INDEPENDENT samples.\n\
#==================================================================\n",
100,
2097152,
1,
diehard_bitstream,
0
};
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