/usr/share/octave/packages/general-1.3.4/@dict/subsasgn.m is in octave-general 1.3.4-1.
This file is owned by root:root, with mode 0o644.
The actual contents of the file can be viewed below.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 | ## Copyright (C) 2009 VZLU Prague, a.s., Czech Republic
##
## This program is free software; you can redistribute it and/or modify it under
## the terms of the GNU General Public License as published by the Free Software
## Foundation; either version 3 of the License, or (at your option) any later
## version.
##
## This program is distributed in the hope that it will be useful, but WITHOUT
## ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or
## FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public License for more
## details.
##
## You should have received a copy of the GNU General Public License along with
## this program; if not, see <http://www.gnu.org/licenses/>.
## -*- texinfo -*-
## @deftypefn{Function File} {d =} subsasgn (d, s, val)
## Overloaded subsasgn for dictionaries.
## @end deftypefn
## Author: Jaroslav Hajek <highegg@gmail.com>
function d = subsasgn (d, s, val)
if (isempty (s))
error ("dict: missing index");
endif
switch (s(1).type)
case "()"
ind = s(1).subs;
if (numel (ind) == 1)
ind = ind{1};
else
error ("dict: needs exactly one index");
endif
if (ischar (ind))
## Scalar assignment case. Search whether the key is present.
i = lookup (d.keys, ind, "m");
if (i)
## The key is present; handle the rest of chain if needed,
## then assign.
if (numel (s) > 1)
val = subsasgn (d.values{i}, s(2:end), val);
endif
d.values{i} = val;
else
## The key is missing; handle the rest of chain if needed.
if (numel (s) > 1)
val = subsasgn ([], s(2:end), val);
endif
## Look up the proper place to insert the new key.
i = lookup (d.keys, ind);
d.keys = [d.keys(1:i,1); {ind}; d.keys(i+1:end,1)];
## Insert value.
d.values = [d.values(1:i,1); {val}; d.values(i+1:end,1)];
endif
elseif (iscellstr (ind))
## Multiple assignment case. Perform checks.
if (numel (s) > 1)
error ("chained subscripts not allowed for multiple fields");
endif
if (isnull (val))
## Deleting elements.
i = lookup (d.keys, ind, "m");
i = i(i != 0);
d.keys(i) = [];
d.values(i) = [];
elseif (iscell (val))
if (numel (val) == 1)
val = repmat (val, size (ind));
elseif (numel (ind) != numel (val))
error ("numbers of elements of index and rhs must match");
endif
## Choose from two paths.
if (numel (ind) < numel (d.keys))
## Scarce assignment. There's a good chance that all keys will be present.
i = lookup (d.keys, ind, "m");
mask = i != 0;
if (all (mask))
d.values(i) = val;
else
d.values(i(mask)) = val(mask);
mask = !mask;
[d.keys, i] = sort ([d.keys; ind(mask)(:)]);
d.values = [d.values; val(mask)(:)](i);
endif
else
## Mass assignment. Probably most of the keys are new ones, so simply
## melt all together.
[d.keys, i] = unique ([d.keys; ind(:)]);
d.values = [d.values; val(:)](i);
endif
else
error ("expected cell rhs for cell index");
endif
else
error ("invalid index");
endif
otherwise
error ("invalid subscript type for assignment");
endswitch
endfunction
|