/usr/lib/python2.7/dist-packages/stdnum/meid.py is in python-stdnum 1.2-1.
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1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 153 154 155 156 157 158 159 160 161 162 163 164 165 166 167 168 169 170 171 172 173 174 175 176 177 178 179 180 181 182 183 184 185 186 187 188 189 190 191 | # meid.py - functions for handling Mobile Equipment Identifiers (MEIDs)
#
# Copyright (C) 2010, 2011, 2012, 2013 Arthur de Jong
#
# This library is free software; you can redistribute it and/or
# modify it under the terms of the GNU Lesser General Public
# License as published by the Free Software Foundation; either
# version 2.1 of the License, or (at your option) any later version.
#
# This library is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
# Lesser General Public License for more details.
#
# You should have received a copy of the GNU Lesser General Public
# License along with this library; if not, write to the Free Software
# Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA
# 02110-1301 USA
"""MEID (Mobile Equipment Identifier).
The Mobile Equipment Identifier is used to identify a physical piece of
CDMA mobile station equipment.
>>> validate('AF 01 23 45 0A BC DE C')
'AF0123450ABCDE'
>>> validate('29360 87365 0070 3710 0')
'AF0123450ABCDE'
>>> validate('29360 87365 0070 3710 0', strip_check_digit=False)
'AF0123450ABCDEC'
>>> validate('29360 87365 0070 3710 1')
Traceback (most recent call last):
...
InvalidChecksum: ...
>>> format('af0123450abcDEC', add_check_digit=True)
'AF 01 23 45 0A BC DE C'
>>> format('af0123450abcDEC', format='dec', add_check_digit=True)
'29360 87365 0070 3710 0'
"""
from stdnum.exceptions import *
from stdnum.util import clean
_hex_alphabet = '0123456789ABCDEF'
def _cleanup(number):
"""Remove any grouping information from the number and removes surrounding
whitespace."""
return clean(str(number), ' -').strip().upper()
def _ishex(number):
for x in number:
if x not in _hex_alphabet:
return False
return True
def _parse(number):
number = _cleanup(number)
if len(number) in (14, 15):
# 14 or 15 digit hex representation
if not _ishex(number):
raise InvalidFormat()
return number[0:14], number[14:]
elif len(number) in (18, 19):
# 18-digit decimal representation
if not number.isdigit():
raise InvalidFormat()
return number[0:18], number[18:]
else:
raise InvalidLength()
def calc_check_digit(number):
"""Calculate the check digit for the number. The number should not
already have a check digit."""
# both the 18-digit decimal format and the 14-digit hex format
# containing only decimal digits should use the decimal Luhn check
from stdnum import luhn
if number.isdigit():
return luhn.calc_check_digit(number)
else:
return luhn.calc_check_digit(number, alphabet=_hex_alphabet)
def compact(number, strip_check_digit=True):
"""Convert the MEID number to the minimal (hexadecimal) representation.
This strips grouping information, removes surrounding whitespace and
converts to hexadecimal if needed. If the check digit is to be preserved
and conversion is done a new check digit is recalculated."""
# first parse the number
number, cd = _parse(number)
# strip check digit if needed
if strip_check_digit:
cd = ''
# convert to hex if needed
if len(number) == 18:
number = '%08X%06X' % (int(number[0:10]), int(number[10:18]))
if cd:
cd = calc_check_digit(number)
# put parts back together again
return number + cd
def validate(number, strip_check_digit=True):
"""Checks to see if the number provided is a valid MEID number. This
converts the representation format of the number (if it is
decimal it is not converted to hexadecimal)."""
from stdnum import luhn
# first parse the number
number, cd = _parse(number)
if len(number) == 18:
# decimal format can be easily determined
if cd:
luhn.validate(number + cd)
# convert to hex
manufacturer_code = int(number[0:10])
serial_num = int(number[10:18])
if manufacturer_code.bit_length() > 32 or serial_num.bit_length() > 24:
raise InvalidComponent()
number = '%08X%06X' % (manufacturer_code, serial_num)
cd = calc_check_digit(number)
elif number.isdigit():
# if the remaining hex format is fully decimal it is an IMEI number
from stdnum import imei
imei.validate(number + cd)
else:
# normal hex Luhn validation
if cd:
luhn.validate(number + cd, alphabet=_hex_alphabet)
if strip_check_digit:
cd = ''
return number + cd
def is_valid(number):
"""Checks to see if the number provided is a valid MEID number."""
try:
return bool(validate(number))
except ValidationError:
return False
def format(number, separator=' ', format=None, add_check_digit=False):
"""Reformat the passed number to the standard format. The separator
used can be provided. If the format is specified (either 'hex' or
'dec') the number is reformatted in that format, otherwise the current
representation is kept. If add_check_digit is True a check digit will
be added if it is not present yet."""
# first parse the number
number, cd = _parse(number)
# format conversions if needed
if format == 'dec' and len(number) == 14:
# convert to decimal
number = '%010d%08d' % (int(number[0:8], 16), int(number[8:14], 16))
if cd:
cd = calc_check_digit(number)
elif format == 'hex' and len(number) == 18:
# convert to hex
number = '%08X%06X' % (int(number[0:10]), int(number[10:18]))
if cd:
cd = calc_check_digit(number)
# see if we need to add a check digit
if add_check_digit and not cd:
cd = calc_check_digit(number)
# split number according to format
if len(number) == 14:
number = [number[i * 2:i * 2 + 2]
for i in range(7)] + [cd]
else:
number = (number[:5], number[5:10], number[10:14], number[14:], cd)
return separator.join(x for x in number if x)
def to_binary(number):
"""Convert the number to its binary representation (without the check
digit)."""
from binascii import a2b_hex
return a2b_hex(compact(number, strip_check_digit=True))
def to_pseudo_esn(number):
"""Convert the provided MEID to a pseudo ESN (pESN). The ESN is returned
in compact hexadecimal representation."""
import hashlib
# return the last 6 digits of the SHA1 hash prefixed with the reserved
# manufacturer code
return '80' + hashlib.sha1(to_binary(number)).hexdigest()[-6:].upper()
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