/usr/share/Yap/heaps.yap is in yap 6.2.2-6.
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1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 153 154 155 156 157 158 159 160 161 162 163 164 165 166 167 168 169 170 171 172 173 174 175 176 177 178 179 180 181 182 183 184 185 186 187 188 189 190 191 192 193 194 195 196 197 198 199 200 201 202 203 204 205 206 207 208 209 210 211 212 213 214 215 216 217 218 219 220 221 222 223 224 225 226 227 228 229 230 231 | % This file has been included as an YAP library by Vitor Santos Costa, 1999
% File : HEAPS.PL
% Author : R.A.O'Keefe
% Updated: 29 November 1983
% Purpose: Implement heaps in Prolog.
/* A heap is a labelled binary tree where the key of each node is less
than or equal to the keys of its sons. The point of a heap is that
we can keep on adding new elements to the heap and we can keep on
taking out the minimum element. If there are N elements total, the
total time is O(NlgN). If you know all the elements in advance, you
are better off doing a merge-sort, but this file is for when you
want to do say a best-first search, and have no idea when you start
how many elements there will be, let alone what they are.
A heap is represented as a triple t(N, Free, Tree) where N is the
number of elements in the tree, Free is a list of integers which
specifies unused positions in the tree, and Tree is a tree made of
t terms for empty subtrees and
t(Key,Datum,Lson,Rson) terms for the rest
The nodes of the tree are notionally numbered like this:
1
2 3
4 6 5 7
8 12 10 14 9 13 11 15
.. .. .. .. .. .. .. .. .. .. .. .. .. .. .. ..
The idea is that if the maximum number of elements that have been in
the heap so far is M, and the tree currently has K elements, the tree
is some subtreee of the tree of this form having exactly M elements,
and the Free list is a list of K-M integers saying which of the
positions in the M-element tree are currently unoccupied. This free
list is needed to ensure that the cost of passing N elements through
the heap is O(NlgM) instead of O(NlgN). For M say 100 and N say 10^4
this means a factor of two. The cost of the free list is slight.
The storage cost of a heap in a copying Prolog (which Dec-10 Prolog is
not) is 2K+3M words.
*/
:- module(heaps,[
add_to_heap/4, % Heap x Key x Datum -> Heap
get_from_heap/4, % Heap -> Key x Datum x Heap
empty_heap/1, % Heap
heap_size/2, % Heap -> Size
heap_to_list/2, % Heap -> List
list_to_heap/2, % List -> Heap
min_of_heap/3, % Heap -> Key x Datum
min_of_heap/5 % Heap -> (Key x Datum) x (Key x Datum)
]).
/*
:- mode
add_to_heap(+, +, +, -),
add_to_heap(+, +, +, +, -),
add_to_heap(+, +, +, +, +, +, -, -),
sort2(+, +, +, +, -, -, -, -),
get_from_heap(+, ?, ?, -),
repair_heap(+, +, +, -),
heap_size(+, ?),
heap_to_list(+, -),
heap_tree_to_list(+, -),
heap_tree_to_list(+, +, -),
list_to_heap(+, -),
list_to_heap(+, +, +, -),
min_of_heap(+, ?, ?),
min_of_heap(+, ?, ?, ?, ?),
min_of_heap(+, +, ?, ?).
*/
% add_to_heap(OldHeap, Key, Datum, NewHeap)
% inserts the new Key-Datum pair into the heap. The insertion is
% not stable, that is, if you insert several pairs with the same
% Key it is not defined which of them will come out first, and it
% is possible for any of them to come out first depending on the
% history of the heap. If you need a stable heap, you could add
% a counter to the heap and include the counter at the time of
% insertion in the key. If the free list is empty, the tree will
% be grown, otherwise one of the empty slots will be re-used. (I
% use imperative programming language, but the heap code is as
% pure as the trees code, you can create any number of variants
% starting from the same heap, and they will share what common
% structure they can without interfering with each other.)
add_to_heap(t(M,[],OldTree), Key, Datum, t(N,[],NewTree)) :- !,
N is M+1,
add_to_heap(N, Key, Datum, OldTree, NewTree).
add_to_heap(t(M,[H|T],OldTree), Key, Datum, t(N,T,NewTree)) :-
N is M+1,
add_to_heap(H, Key, Datum, OldTree, NewTree).
add_to_heap(1, Key, Datum, _, t(Key,Datum,t,t)) :- !.
add_to_heap(N, Key, Datum, t(K1,D1,L1,R1), t(K2,D2,L2,R2)) :-
E is N mod 2,
M is N//2,
% M > 0, % only called from list_to_heap/4,add_to_heap/4
sort2(Key, Datum, K1, D1, K2, D2, K3, D3),
add_to_heap(E, M, K3, D3, L1, R1, L2, R2).
add_to_heap(0, N, Key, Datum, L1, R, L2, R) :- !,
add_to_heap(N, Key, Datum, L1, L2).
add_to_heap(1, N, Key, Datum, L, R1, L, R2) :- !,
add_to_heap(N, Key, Datum, R1, R2).
sort2(Key1, Datum1, Key2, Datum2, Key1, Datum1, Key2, Datum2) :-
Key1 @< Key2,
!.
sort2(Key1, Datum1, Key2, Datum2, Key2, Datum2, Key1, Datum1).
% get_from_heap(OldHeap, Key, Datum, NewHeap)
% returns the Key-Datum pair in OldHeap with the smallest Key, and
% also a New Heap which is the Old Heap with that pair deleted.
% The easy part is picking off the smallest element. The hard part
% is repairing the heap structure. repair_heap/4 takes a pair of
% heaps and returns a new heap built from their elements, and the
% position number of the gap in the new tree. Note that repair_heap
% is *not* tail-recursive.
get_from_heap(t(N,Free,t(Key,Datum,L,R)), Key, Datum, t(M,[Hole|Free],Tree)) :-
M is N-1,
repair_heap(L, R, Tree, Hole).
repair_heap(t(K1,D1,L1,R1), t(K2,D2,L2,R2), t(K2,D2,t(K1,D1,L1,R1),R3), N) :-
K2 @< K1,
!,
repair_heap(L2, R2, R3, M),
N is 2*M+1.
repair_heap(t(K1,D1,L1,R1), t(K2,D2,L2,R2), t(K1,D1,L3,t(K2,D2,L2,R2)), N) :- !,
repair_heap(L1, R1, L3, M),
N is 2*M.
repair_heap(t(K1,D1,L1,R1), t, t(K1,D1,L3,t), N) :- !,
repair_heap(L1, R1, L3, M),
N is 2*M.
repair_heap(t, t(K2,D2,L2,R2), t(K2,D2,t,R3), N) :- !,
repair_heap(L2, R2, R3, M),
N is 2*M+1.
repair_heap(t, t, t, 1) :- !.
% heap_size(Heap, Size)
% reports the number of elements currently in the heap.
heap_size(t(Size,_,_), Size).
% heap_to_list(Heap, List)
% returns the current set of Key-Datum pairs in the Heap as a
% List, sorted into ascending order of Keys. This is included
% simply because I think every data structure foo ought to have
% a foo_to_list and list_to_foo relation (where, of course, it
% makes sense!) so that conversion between arbitrary data
% structures is as easy as possible. This predicate is basically
% just a merge sort, where we can exploit the fact that the tops
% of the subtrees are smaller than their descendants.
heap_to_list(t(_,_,Tree), List) :-
heap_tree_to_list(Tree, List).
heap_tree_to_list(t, []) :- !.
heap_tree_to_list(t(Key,Datum,Lson,Rson), [Key-Datum|Merged]) :-
heap_tree_to_list(Lson, Llist),
heap_tree_to_list(Rson, Rlist),
heap_tree_to_list(Llist, Rlist, Merged).
heap_tree_to_list([H1|T1], [H2|T2], [H2|T3]) :-
H2 @< H1,
!,
heap_tree_to_list([H1|T1], T2, T3).
heap_tree_to_list([H1|T1], T2, [H1|T3]) :- !,
heap_tree_to_list(T1, T2, T3).
heap_tree_to_list([], T, T) :- !.
heap_tree_to_list(T, [], T).
% list_to_heap(List, Heap)
% takes a list of Key-Datum pairs (such as keysort could be used to
% sort) and forms them into a heap. We could do that a wee bit
% faster by keysorting the list and building the tree directly, but
% this algorithm makes it obvious that the result is a heap, and
% could be adapted for use when the ordering predicate is not @<
% and hence keysort is inapplicable.
list_to_heap(List, Heap) :-
list_to_heap(List, 0, t, Heap).
list_to_heap([], N, Tree, t(N,[],Tree)) :- !.
list_to_heap([Key-Datum|Rest], M, OldTree, Heap) :-
N is M+1,
add_to_heap(N, Key, Datum, OldTree, MidTree),
list_to_heap(Rest, N, MidTree, Heap).
% min_of_heap(Heap, Key, Datum)
% returns the Key-Datum pair at the top of the heap (which is of
% course the pair with the smallest Key), but does not remove it
% from the heap. It fails if the heap is empty.
% min_of_heap(Heap, Key1, Datum1, Key2, Datum2)
% returns the smallest (Key1) and second smallest (Key2) pairs in
% the heap, without deleting them. It fails if the heap does not
% have at least two elements.
min_of_heap(t(_,_,t(Key,Datum,_,_)), Key, Datum).
min_of_heap(t(_,_,t(Key1,Datum1,Lson,Rson)), Key1, Datum1, Key2, Datum2) :-
min_of_heap(Lson, Rson, Key2, Datum2).
min_of_heap(t(Ka,_Da,_,_), t(Kb,Db,_,_), Kb, Db) :-
Kb @< Ka, !.
min_of_heap(t(Ka,Da,_,_), _, Ka, Da).
min_of_heap(t, t(Kb,Db,_,_), Kb, Db).
empty_heap(t(0,[],t)).
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